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Let's do this question if one of the angles of a triangle is a hundred and ten degree, then the angle

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between the bicyclers of the other two angles is all right.

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Also the video, give it a try and then let's do it together.

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All right.

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We are back.

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So let me draw a triangle, ABC over here.

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And it's given that one of the angles is equal to a hundred and ten degrees.

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All right.

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Now let's draw the angle by sectors of the other two angles and they are intersecting over here.

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Now, let's mark these three angles as angle one and two and angle three.

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Now, the question is, we need to find angle three right now.

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Let's press on we know angle A plus angle B plus angle is equal to 180 degrees as per the angle, some

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property of a triangle.

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So hundred and ten plus angle B plus angle sees equal to 180 degrees.

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Or we can say that angle B plus Anglesey is equal to 70 degrees.

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All right.

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Now, because this railway here is the angle by sector of angle B, therefore I can see that angle one

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is equal to half of angle B.

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Similarly, angle two is equal to half of angle C right now.

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Let's name this as all.

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Now all we see is a triangle right there for angle one plus angle two plus angle three is equal to 180

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degrees.

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Now let me substitute in sort of angle one, angle B by two and instead of angle to angle see by two.

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So that gives us angle B plus angle see by two plus angle three is equal to 180 degrees.

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Right now we know angle B plus angle is 70 degrees.

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So angle B plus angle C by two is seventy by two to seventy by two plus angle three is equal to 180

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degrees, 70 by two is thirty five to angle three is equal to 180 minus thirty five, which is equal

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to one forty five degrees.

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So your answer is option the.
