Let's do this question if one of the angles of a triangle is a hundred and ten degree, then the angle
between the bicyclers of the other two angles is all right.
Also the video, give it a try and then let's do it together.
All right.
We are back.
So let me draw a triangle, ABC over here.
And it's given that one of the angles is equal to a hundred and ten degrees.
All right.
Now let's draw the angle by sectors of the other two angles and they are intersecting over here.
Now, let's mark these three angles as angle one and two and angle three.
Now, the question is, we need to find angle three right now.
Let's press on we know angle A plus angle B plus angle is equal to 180 degrees as per the angle, some
property of a triangle.
So hundred and ten plus angle B plus angle sees equal to 180 degrees.
Or we can say that angle B plus Anglesey is equal to 70 degrees.
All right.
Now, because this railway here is the angle by sector of angle B, therefore I can see that angle one
is equal to half of angle B.
Similarly, angle two is equal to half of angle C right now.
Let's name this as all.
Now all we see is a triangle right there for angle one plus angle two plus angle three is equal to 180
degrees.
Now let me substitute in sort of angle one, angle B by two and instead of angle to angle see by two.
So that gives us angle B plus angle see by two plus angle three is equal to 180 degrees.
Right now we know angle B plus angle is 70 degrees.
So angle B plus angle C by two is seventy by two to seventy by two plus angle three is equal to 180
degrees, 70 by two is thirty five to angle three is equal to 180 minus thirty five, which is equal
to one forty five degrees.
So your answer is option the.