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I students in this video, let's discuss a very important and useful property in right angle triangles

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called the Pythagoras's theorem or the Pythagoras's property.

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All right, so let's take an example of a right angle triangle.

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This angle over here is a 90 degree angle.

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And we call the side opposite to the angle that makes a 90 degree as the hypotenuse to this side over

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here is opposite to the 90 degree angle.

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And we call that the hypotenuse.

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All right.

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Now, the other two sides are legs of the right angle triangle.

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Now let's move on.

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We have defined these terms.

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Remember what the hypotenuse is?

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It's the side opposite the 90 degree angle.

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All right.

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Now let's take a right angle triangle.

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We have a triangle with sides A, B and C, and this is a right angle triangle with a 90 degree angle

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over here.

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All right.

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Let's make three more copies of this right angle triangle.

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All right.

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And let's change the arrangement of these four triangles in this manner.

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Now, let's make a copy of this over here.

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OK, now you will see that this area over here is equal to a into a that's a square, right?

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Because over here you get a square.

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Let me name this figure a, b, c, d, e, f, g, and it's now B, B if it is A square.

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And each of its sites is of lengthy.

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We know that the area of a square is a into a you can check more about it under quadrilaterals.

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Now, the area of a square is site square lower here.

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Every site is equal to eight.

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Therefore, the area of this square is equal to a square.

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All right.

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Now the site, the angles of a square are 90 degrees.

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Now, this angle will be equal to 90 degrees.

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Why would that be?

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Let me quickly show you that let's construct a line that's parallel to AC.

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And over here now, we can see that this angle will be equal to this angle.

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Let me call this angle one.

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So this is also angle one.

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And you will see that this angle over here will be equal to this angle.

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Let me call this angle to angle to why is that so?

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Because these are alternate interior angles, right?

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This line over here, which we constructed, let me call it, as Lynelle is parallel to G and it's parallel

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to AC.

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Therefore, this angle and this angle are equal.

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Similarly, this angle and this angle are equal.

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Right.

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And we started with the right angle triangle.

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Right.

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This angle will be angled to and this is 90 degrees.

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So we know that as our angles and property angle one plus angle two plus this angle over here, which

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is 90 degrees, is equal to 180 degrees.

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Therefore angle one plus angle two is equal to 180 minus 90, which is equal to 90.

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Right.

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That's why this angle is 90 degrees and each side is of length.

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That's why BATF is it square.

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And we know that the area of a square is equal to a new A or side in the side.

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And in this case, the area is equal to a square.

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All right.

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Now let's move on.

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We have made a copy of this shape over here and we have a square as the uncovered area in this case.

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Right.

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All right, now let's make some arrangement shifting in the case of these triangles and see what happens,

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I shift this triangle in this direction.

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And it goes over here.

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All right, now the boundary is the same, you cannot all right, now this triangle is shifted in this

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direction.

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And this triangle over here, I shifted down.

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All right, now we have maintained the boundary as the same right there for the area of uncovered,

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which is uncovered over here as to be equal to the uncovered area over here.

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What do I mean with uncovered area?

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It's the area that is not occupied by a triangle.

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Over here.

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You can see this is occupied by a triangle.

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This is occupied by triangle.

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This is occupied by triangle.

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This is occupied by triangle.

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The remaining area is what we call the uncovered area over here.

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We have shifted the triangle such that this is the area covered by a triangle.

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This is the uncovered area.

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All right.

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Now, what is this area?

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This is equal to being to be which is equal to be square.

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Right.

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Because you can see that this site is B and this side is B, so we are getting a square of side B over

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here.

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Similarly, you can see that over here, this site is of lengthy and this site is of Benghazi and we

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are getting a square of sight to see.

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So the area over here is equal to C Square.

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Now, because the uncovered areas have to be equal and the uncovered area over here is equal to a square

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and the uncovered area over here is equal to be squared plus C squared, therefore is square, is equal

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to B squared plus C square.

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And remember, what is a BNC?

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These are sides of the triangle with which we started, which is a right angle.

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Triangle is the hypotenuse, which is the side opposite the 90 degree angle.

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Therefore this is what we call the Pythagoras theorem that is in a right angle triangle.

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The square of the hypotenuse is equal to the sum of the squares of the other two sides.

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That is a square is equal to B squared plus C square.

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And remember, the Pythagoras property is valid only for the right angle triangles and this is the right

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angle triangle.

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That is why this is true.

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So let's quickly summarize.

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You take any right angle triangle.

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Let's take an example or let it be five.

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Let this be three and let this before this and ninety degree angle, you will see that five square is

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equal to three square plus or square.

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What is five square.

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That's twenty five.

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What is three square.

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That's nine.

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What is four square.

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That's sixteen and nine plus sixteen you will see is equal to twenty five.

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So in a right angle triangle the square of the hypotenuse is equal to the sum of the squares of the

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other two sides and that is what we call the Pythagoras property.
