1
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Let's do this question in a triangle, the longest side is 20 centimeter.

2
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Another side is 15 centimeter.

3
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The area of the triangle is 90 square centimeter.

4
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Find the third side.

5
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All right.

6
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So we have BK's equal to 20 abs, equal to 15, and we need to find the value of AC.

7
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All right.

8
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Pause the video, give it a try, and then let's do it together.

9
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All right.

10
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We're back.

11
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I hope you've given it a try.

12
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Let's do it together.

13
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Let's drop a perpendicular from point A to cite B, C.

14
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All right, this is our height and let this point be OK now we have seen that the area of the triangle

15
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is half.

16
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Based in the height.

17
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Right over here, let's take 20 as the base, if you take 20 as the base, then the height is this length

18
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over here, right?

19
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It's the perpendicular distance from the opposite vertex.

20
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To decide if I was to take a B as the base, then the height would be the perpendicular distance from

21
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point C to side A B, right.

22
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And if I have to take AC as the base, the height would be the perpendicular distance from point B to

23
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side easy.

24
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All right, now let's move on or here we are taking B.C. as the base and the height is the perpendicular

25
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distance from point A, which is the opposite vertex to B.C. And we have marked it as it's now it's

26
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given that the area is equal to 90 square centimeter, therefore half in twenty two is equal to ninety.

27
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So I can cut out two from the numerator and the denominator.

28
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So I get X equal to nine centimeter.

29
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All right.

30
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Now A B or is it right angled triangle.

31
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Right.

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You can see that this angle over here is a 90 degree angle because that's how we take the height.

33
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And as per Pythagoras's theorem, we can find that 15 square is equal to eight squared plus or B square,

34
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and we have found that it is equal to nine.

35
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So 15 squared is equal to nine squared plus or B squared.

36
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15 squared is 225.

37
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Nine squared is eighty one.

38
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So 225 minus eighty one gives you one forty four.

39
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Therefore Albe Square is equal to one forty four or B is equal to square root of one forty four which

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is equal to twelve.

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All right.

42
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But we have found that obese 12, we know BK's 20, therefore C will be twenty minus twelve which is

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equal to eight centimetre.

44
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Now let's mark that over here.

45
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We have Oak's eight centimetre now a C or is also a right angle triangle.

46
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Right.

47
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Therefore ASBA Pythagoras's Theorem X squared is equal to.

48
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It's square or a square plus orthey square.

49
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We know it his name and we have found all eight.

50
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Therefore Square is nine square plus eight square.

51
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That's eighty one plus sixty four, which is equal to one forty five.

52
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Therefore X equals the square root of one forty five.

53
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And that's approximately 12.

54
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Right.

55
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Because we know 12 square is equal to one forty four, which is very close to one forty five.

56
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And that is your answer.
