Let's do this question in the given figure peak, you are this is a rectangle right now is equal to
you as you are.
So these three nine segments are equal in the ratio of the area of P, Q, D This part over here and
the area of Triangle T u u.
That's this spot over here.
Right.
Now pause the video, give it a try, and then let's do it together.
All right, we're back.
I hope you've given it a try.
Let's do it together.
Now, over here, you can see that there is a very interesting method with which we can very quickly
solve this question, and you are points such that the tricyclic the main segment is right.
What does that mean?
Estie is equal to you?
Is equal to you.
And that is given.
Now, let's take two points on PKU that do the same and let's join it with S right.
So you get this type of a construction.
Now let's join D at this point and you get this type of a construction right now.
You can see that by doing this you have achieved six triangles of equal area.
These are the six triangles of equal area.
Now, why are these triangles of equal area?
You will see that these triangles are between parallel lines and their base is equal.
Right.
So these triangles have equal base.
And they are between two parallel lines, why are they between parallel lines, because opposite sides
of a rectangle are parallel, right?
And why do they have an equal base?
Let's see that in the case of triangle, let's name it us and be over here.
So in the case of Triangle, it's B.
T, you can see that Estie is the base, that's X. Let's take that as X in the case of Triangle Kikue
you also the base is X and in the case of Triangle UCU are the bases X, right.
We have seen that it's given now we have taken point and be such that base is equal to AB BQ.
So again these bases are also X, so that's why these six triangles have the same base of length X and
the height is the same, which is you are because these are parallel lines, because when S.R. are parallel
lines and we know that this angle in a rectangle is 90 degrees.
So the height between two parallel lines in this case is Kuhar, which is a it's therefore we can see
that the area of each of these six triangles is half in the X into X and these six triangles have the
same area.
Now we need to find the ratio of P qst to the ratio of any of T Q you.
All right.
Now we just need to find the ratio.
Remember, we don't need to find the absolute value of any of these.
We just need to find the ratio and we cannot find the absolute value also because no absolute value
is given in the question right now.
BQ, that's p q s p p q it's alright aspects right p.
Q As you can see that it has one, two, three, four.
Or of these triangles of equal area are included in P, q these and indeed Q You, you have just one
triangle of equal area.
So if the area of this triangle is a area of trying area of P, Q, D will be for a, an area of D,
Q You will be one that is forty and one and that it gets cancelled out.
Therefore the ratio between area of P, Q, D and D Q is equal to four, divided by one.