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Let's do this question in the given figure peak, you are this is a rectangle right now is equal to

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you as you are.

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So these three nine segments are equal in the ratio of the area of P, Q, D This part over here and

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the area of Triangle T u u.

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That's this spot over here.

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Right.

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Now pause the video, give it a try, and then let's do it together.

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All right, we're back.

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I hope you've given it a try.

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Let's do it together.

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Now, over here, you can see that there is a very interesting method with which we can very quickly

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solve this question, and you are points such that the tricyclic the main segment is right.

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What does that mean?

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Estie is equal to you?

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Is equal to you.

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And that is given.

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Now, let's take two points on PKU that do the same and let's join it with S right.

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So you get this type of a construction.

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Now let's join D at this point and you get this type of a construction right now.

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You can see that by doing this you have achieved six triangles of equal area.

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These are the six triangles of equal area.

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Now, why are these triangles of equal area?

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You will see that these triangles are between parallel lines and their base is equal.

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Right.

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So these triangles have equal base.

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And they are between two parallel lines, why are they between parallel lines, because opposite sides

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of a rectangle are parallel, right?

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And why do they have an equal base?

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Let's see that in the case of triangle, let's name it us and be over here.

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So in the case of Triangle, it's B.

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T, you can see that Estie is the base, that's X. Let's take that as X in the case of Triangle Kikue

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you also the base is X and in the case of Triangle UCU are the bases X, right.

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We have seen that it's given now we have taken point and be such that base is equal to AB BQ.

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So again these bases are also X, so that's why these six triangles have the same base of length X and

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the height is the same, which is you are because these are parallel lines, because when S.R. are parallel

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lines and we know that this angle in a rectangle is 90 degrees.

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So the height between two parallel lines in this case is Kuhar, which is a it's therefore we can see

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that the area of each of these six triangles is half in the X into X and these six triangles have the

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same area.

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Now we need to find the ratio of P qst to the ratio of any of T Q you.

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All right.

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Now we just need to find the ratio.

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Remember, we don't need to find the absolute value of any of these.

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We just need to find the ratio and we cannot find the absolute value also because no absolute value

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is given in the question right now.

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BQ, that's p q s p p q it's alright aspects right p.

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Q As you can see that it has one, two, three, four.

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Or of these triangles of equal area are included in P, q these and indeed Q You, you have just one

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triangle of equal area.

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So if the area of this triangle is a area of trying area of P, Q, D will be for a, an area of D,

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Q You will be one that is forty and one and that it gets cancelled out.

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Therefore the ratio between area of P, Q, D and D Q is equal to four, divided by one.