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Let's do this question in a right angle triangle, the length of the shortest median is 15 centimeter.

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If the area of the triangle is two one six square centimeter, find the length of the longest median.

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All right.

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Was the video.

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Give it a try and then let's do it together.

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All right, we're back, I hope you have given it a try.

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Let's do it together.

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Let's draw a rough sketch.

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We have a right angle triangle over here.

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Now, you can observe that the shortest median will be to the longest side and the vice versa is also

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true.

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That is the longest median will be to the shortest side.

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All right, now, this is a 90 degree angle right there for this side over here is the hypotenuse that

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is it's the longest side.

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Therefore, this median will be the shortest median right now.

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It's given that the shortest median is equal to 15 centimetre.

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Right.

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Now, let me name this triangle as triangle ABC, now AC is equal to 30 centimeters, right?

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Why is that so?

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Because we have a right angle triangle and we have drawn a median to the hypotenuse, remember?

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Therefore, if this is X, this also will be X and this also will be X.

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If I call this point a SPE, then AP is equal to pieces equal to BP because point B is these Sock'Em

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Center.

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All right, so we have found that AC is equal to 30 centimeter centimetre right now, let me call abs

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X and B C white.

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So the length of ABS X and the length of B C is white.

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Now, as per Pythagoras's theorem, we know that X squared plus Y square is equal to 30 square because

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X the hypotenuse.

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Right.

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And it's also given that the area of the triangle is two hundred and sixteen now because this is the

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right angle triangle, the altitude from point A is A itself.

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We know that the area of a triangle is half base into height.

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So the area of this triangle can be taken as 1/2 X and Y.

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That's equal to two hundred and sixteen.

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Right.

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Therefore X and Y is equal to two hundred and sixteen in the two, which is equal to four hundred and

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thirty two.

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All right.

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Now let's try to solve these two equations now before we go ahead and make it into a quadratic equation.

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We can easily solve it using trial and error substitution.

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Let's take an example.

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We know that three, four and five are forming a Pythagorean Triplette.

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Right.

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And over here, we know one side is 30 centimetre.

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That is the hypotenuse.

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So if I want to get five to 30, I need to multiply it with six.

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Right.

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So five in the six gives me thirteen.

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Now let me multiply three and four also with six.

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So that gives me 18 and twenty four.

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And let's check whether 18 and 24 satisfies X, Y is equal to 42.

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Let's try that to 18 to twenty four.

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If you do that you will get 42.

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Therefore it is satisfied and hence X and Y is equal to 18 and 24.

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All right.

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Now we need to find the length of the longest median.

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The length of the longest median will be to the shortest side.

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So let's take Y as the shortest side.

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So in that case, this will be the longest median right now.

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Let's press on to this length over here.

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That's BP is equal to nine centimetre because B is the point of B, C, right.

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Because we are talking about a median eppy.

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So we know B.C. has to be the shortest side.

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And among eighteen twenty four, eighteen is the shortest one.

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So therefore we have taken BK's 18 and we have got BP s nine.

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All right.

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Now let's proceed over here.

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We know X is equal to twenty four.

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Right.

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So let's right that over here and we have a right angle.

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Triangle A, B, B to aspart Pythagoras's theorem.

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We know a B squared is equal to twenty four squared plus nine squared.

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That gives us six hundred and fifty seven and eight.

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B will be the square root of six hundred and fifty seven and that's equal to three root seventy three.

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That is your answer.
