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Let's do this question in an isolationist triangle.

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One of the angles equals hundred degrees, find the other two angles.

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All right.

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Was the video.

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Give it a try and then let's do it together.

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All right.

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We are back.

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I hope you're giving it a try.

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Let's do it together.

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Over here.

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We have an isosceles triangle.

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We know that in an isolationist triangle, two angles are equal, right?

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So that these two angles be equal to X degree.

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And we know as per the angles and property of triangles, two X plus why is equal to 180 degrees.

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Now there are two options.

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We know that one of the angles is equal to one hundred degree.

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So either this angle and this angle could be 100 degree or this angle could be one hundred degrees.

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Now let's try putting X is equal to hundred degrees.

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Would that work if we put X is equal to hundred degrees?

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You can see that over here you have 100 degrees and over here you have hundred degrees.

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So two in two hundred plus white, that cannot be equal to 180.

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Right.

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This itself is two hundred, but this is going about 180 degrees.

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So this cannot be the correct approach.

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So X cannot be equal to under degrees.

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Therefore why has to be equal to 100 degrees.

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Now if we put Y equals two hundred degrees we get two X plus hundred is equal to 180 degrees or we get

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X is equal to 40 degrees.

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Therefore the two angles are 40 and 40.

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And that is your answer.