Let's do this question in an isolationist triangle.
One of the angles equals hundred degrees, find the other two angles.
All right.
Was the video.
Give it a try and then let's do it together.
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Let's do it together.
Over here.
We have an isosceles triangle.
We know that in an isolationist triangle, two angles are equal, right?
So that these two angles be equal to X degree.
And we know as per the angles and property of triangles, two X plus why is equal to 180 degrees.
Now there are two options.
We know that one of the angles is equal to one hundred degree.
So either this angle and this angle could be 100 degree or this angle could be one hundred degrees.
Now let's try putting X is equal to hundred degrees.
Would that work if we put X is equal to hundred degrees?
You can see that over here you have 100 degrees and over here you have hundred degrees.
So two in two hundred plus white, that cannot be equal to 180.
Right.
This itself is two hundred, but this is going about 180 degrees.
So this cannot be the correct approach.
So X cannot be equal to under degrees.
Therefore why has to be equal to 100 degrees.
Now if we put Y equals two hundred degrees we get two X plus hundred is equal to 180 degrees or we get
X is equal to 40 degrees.
Therefore the two angles are 40 and 40.
And that is your answer.