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Students in this video, let's discuss equilateral triangles in great detail.

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So far we have seen that equilateral triangles are triangles where all the sides are equal.

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So in this case, let each side be of length A.

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All right, now in an equilateral triangle, we have also seen that all the angles are equal in every

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angle is equal to 60 degrees, right.

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Because we know that the sum of the angles of a triangle are 180 degrees.

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All right.

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Now, let me draw a line from this vertex to the base such that it is splitting the base into two equal

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halves.

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Two, I draw the line over here such that BD is equal to D.C. or D, the midpoint of B.C..

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All right.

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Now you can see that if you analyze triangle abeed, that is this triangle over here and Triangle ADC,

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that is the triangle over here.

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You can see that these two triangles are congruent Asper as as is criteria.

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Right.

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Why are they.

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So you have this site equal to this side because both is equal to it.

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We have seen that this is the midpoint of B.C. So beauty is equal to D.C. and it is a common sight to

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all the three sides of these two triangles are equal and hence, as per Essence's criteria, Triangle

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Abdeh and Triangle ADC are congruent.

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All right.

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Now, therefore, we can conclude that Angle and B will be 90 degrees.

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Right?

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Why?

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Because let me right that over here.

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Angle A B B is equal to angle E DC because they are corresponding angles of two congruent triangles.

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And you can see from the diagram that they form a linear pair.

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Right.

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And we know that a linear pair adds up to 180 degrees.

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So say this is X degrees, this is also X degrees.

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That means X plus X or two.

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X is equal to 180 degree or X is equal to 90 degrees.

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That's why this angle over here will be 90 degrees.

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All right.

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Now, if side B, C is of length E and we know D, the midpoint of B, C, therefore B is of length

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EBITA.

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Right now, over here we have a right angle triangle, right triangle beauty.

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And the hypotenuse is upside it and another side is of length EBITA.

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Therefore we can find that aid, which is the height of this triangle.

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It's equal to the square root of a square minus Ebeye to the whole square.

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Right.

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Why is this.

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So this is an upper Pythagoras theorem.

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Right.

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Because we know is square is equal to it by two the whole square plus it's square and remember it's

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over here.

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Is it right now from here I find that edge is the square root of square minus two.

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The whole square.

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All right, let me make some space over here.

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All right, now on simplifying this equation, we get that the height of the equilateral triangle can

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be described as rude prebuy to a.

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So the Heidi's route three by two.

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So we have found the height of the equilateral triangle in terms of the side of the equilateral triangle.

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All right.

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Now let's find the area of this equilateral triangle.

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We know that area of a triangle is half base in the height.

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Right.

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All right.

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So let me take B.C. as the base that's of length.

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And I know that the height is Route three by two.

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So that's half in to a new route three by two.

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And that gives me Route three by four square.

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And that is the equation which we can use to find the area of an equilateral triangle.

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So let's quickly revise.

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We have seen that in a little triangle.

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All the sides are equal and all the angles are equal and the angles are equal to 60 degrees.

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All right.

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And we have seen that the line segment, which is dividing the opposite side of Vertex into two equal

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halves, is also a perpendicular line segment.

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That is we have seen angle.

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It is 90 degrees later we will see that this is the median as well as the perpendicular bisecting.

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All right.

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That will be following up in future video.

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Now, let's press on.

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We have seen that the height of the equilateral triangle is equal to Route three by two.

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So in this way, we have expressed the height of the triangle in terms of the side of the triangle.

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And we have seen that the area of the triangle is equal to room three by four, a square.
