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Let's do this question in the figure below.

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Find the sum of the ingredients of Triangle B, Q, R and Triangle P, as are.

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All right.

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Was the video.

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Give it a try and then let's do it together.

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All right.

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We're back.

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Let's do it together.

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Over here.

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You can see that.

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Twenty, fifteen and twenty five.

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That is the three sides of triangle P.

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Q is form a Pythagoras triplet.

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Right.

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Why is that so.

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The first reason is you can see twenty five squared is equal to twenty squared plus fifteen squared.

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Right.

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And we have discussed other numbers how to find quickly squares of numbers.

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Right.

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And there is also a different way in which you can find that this is a Pythagoras triplet.

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You can quickly observe that it's related to the Pythagorean Triplette five, four, three.

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Now take this Pythagoras Triplette and multiply throughout with five.

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So over here, five into five gives you twenty five or in the five gives you twenty and three in the

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five gives you fifteen.

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So we have already seen that if you take it by the intraplate and multiply it throughout with the number,

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you will get another by the intraplate.

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All right.

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Now having established that twenty fifteen and twenty five former Pythagorean Triplette, therefore

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Angle Kupets will be a 90 degree angle, right.

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This angle will be a 90 degree angle.

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Let's mark the length B are as it's.

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All right, now we know that the area of a triangle is equal to half base in height.

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Now let's take 15 as the base, then 20, that is space would be the height, right?

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If BQ is the base B, as is the height.

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So I can right the area of this triangle as half in the 15 or 20.

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Or if Q is the base then P R is the height.

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Right.

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Because this angle has to be 90 degrees over your base is the height because this angle is 90 degrees.

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All right.

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So if QSA is the base bar is the height.

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So they African wilderness often took us into B-R or it's all right.

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So let's right that.

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So I have half in the 15 and 20, which is the area and we also have half in to us.

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That's twenty five in the edge as the area.

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Therefore I can equate these two expressions because it's giving us the same area that is the area of

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Triangle Kupets.

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All right.

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Now using this equation, I can find that it is equal to twelve, right?

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Often half gets cancelled out.

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Over here you have 15.

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So you divide it by five, you get three to divide this by fire, you get five and five.

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Cut it out from both sides and you're left with four.

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So you get it is equal to three in the four, which is equal to twelve to the height over here is twelve

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centimeter.

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All right.

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Now let's take a triangle to our peak.

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The Triangle Q, r B is also a right angle triangle.

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Right.

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Therefore side Q are can be found as root of 15 square minus 12 square.

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That gives you nine.

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Why is that so.

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Because this is the hypotenuse.

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Right.

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But we know 15 square is equal to Q are squared plus it's square and that is twelve.

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Right.

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Well squared.

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So take this to the other side and you get.

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Q What is the square root of 15 square.

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Minus 12 square that gives you eighty one and square root of eighty one gives you nine.

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So QR is equal to nine, therefore ours would be twenty five minus nine.

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Right.

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Which is equal to sixteen.

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All right.

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Now we have established this over here.

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Let me right this over here.

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Q Are is nine and ours is equal to sixteen.

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So let's take this aside.

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All right, now let me market over here again.

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We have nine and 16 over here and it is equal to 12 already in triangle because you are in this triangle.

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You can see that half you are into it will give you the area.

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Right, because this angle is 90 degrees.

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Therefore, half base in the height is the area that is half you are into it.

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And we have seen that the area of a triangle can also be found as the product of the in radius and the

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semi perimeter.

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So of you are into it is equal to our into S1 where R-1 is the semi inside Iran is the radius of triangle.

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You are an S1 is the same perimeter of trying to pick you up.

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All right.

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So let's substitute the values that gives us nine by two in the 12th is equal to 18 into our.

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As one is equal to 18.

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Right.

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How do you find that 15 plus nine plus 12.

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That gives you 36.

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Right.

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And 36 by two.

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Gives you 18.

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All right, let's press on.

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So from this equation, we can find that R-1 is equal to three.

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So the radius of Triangle Park you are is equal to three centimeter.

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Similarly, let's take triangle B.

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R.

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S.

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We can ride off into 16 and 12 is equal to our two in the S2 and S2 is equal to forty eight by two,

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which gives you twenty four.

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Right.

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So using this equation you can find that our two is equal to four centimetre and you are asked to find

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the sum of the radiuses.

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So that would be R one plus R two which is equal to three plus four.

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That gives you the answer seven centimetre.

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Now in the next video we learn a shortcut to do the same thing much faster.
