Let's do this question in the figure BQ is the angle by sector of Angle EPB.
All right, so this angle over here is equal to this angle.
Now, PR is the angle by sector of angle A, B, C, this angle over here is equal to this angle over
here.
B, C is giving us 10 centimeter equals six centimeter, BQ is three centimeter and AC is 14 centimeter.
Now we need to find B B if the ratio of A R to ask E R to us is to is to one already.
Pause the video, give it a try and then let's do it together.
All right, we're back.
Let's do it together as per the interior angle bisected theorem, right in this or in this case over
here, we can say that BP by P will be equal to BQ by it.
Right.
BP by is equal to be Kubi because you is the angle by sector of this angle over here.
Now we know that BQ is three centimeter and Q is six centimeters.
So that's three by six, which gives me one by two.
Now over here P R is the angle by sector of angle ipse.
Therefore be it by proxy will be equal to a R by Arcy, right by R by Arcy.
Now it's given that the ratio of error to ask is two is to one.
So this is equal to two by one.
All right.
Now.
From this part over here, I know that BP by BP is equal to one by two, right?
So I can write to BP, is it going to be it by cross multiply the two.
BP is equal.
Luppi now over here I have B by proxy is equal to two by one, therefore by cross multiplying.
I can say that to C is equal to be it.
Now over here we have B and over here we have B, therefore to BP is equal to C or cancelling out to
from both the sides.
We can see that BP is equal to P.c.
That means this side over here is equal to this site over here now because B C is the sum of BP plus
B.C. Therefore each of these will be B, C, divided by two.
All right.
Now, over here, it's given that BK's equal to 10 centimetre.
Therefore, this is equal to ten by two, which gives you five centimetre.
And that is your answer, right?
You need to find BP.
So BP's five centimetre.