Let's do this question in the figure is equal to 20 centimeter BQ is to cure is to ask you is equal
to three is to do is to one answer is the angle by sector of angle T.
S Q This angle over here.
All right.
Find the inner radius of triangle B askew.
This triangles in radius is what we need to find.
All right.
Was the video.
Give it a try and then let's do it together.
All right.
We are back.
Let's do it together.
Let's mark the information that is given in the question piece is equal to twenty centimeter and P Q
is too curious to ask you is three is to do is to one.
Therefore I can write because three x Q R as two X and ask you as X.
Alright now over here we have an external angle by sector.
Remember to write the ratios correctly.
Imagine that it's an internal angle by sector.
Right.
So imagine as far as the internal angle by sector then we know that the ratio is pIace by SKU is equal
to P R by our Q right.
So let's write that over here because my skill is equal to PR by our Q And now we remove the imagination
that this is an internal angle by sector.
So we are back and we have the required ratio return correctly.
Now let's plug in the values we know P as is equal to twenty askew is equal to x p, r is three X plus
two weeks and argue that's two X.
So let's write the values.
Twenty by X is equal to three X plus two weeks by two X that is twenty by X is equal to five by two
or on simplifying you get X is equal to four in the two or eight.
So let's write the sides of this triangle over here.
We have the sides of triangle be as good as twenty, twenty four and eight.
Alright so what is the semi perimeter.
That's twenty plus twenty four plus eight which is fifty two.
Divided by two.
Right.
The semi perimeter is fifty two by two which gives you twenty six.
All right.
Now as per her own formula, what is the area of triangle bascule that's square root of S into S minus
E in the S minus B into S minus C.
Right.
So that's equal to square root of twenty six into six in the two in the eighteen.
Right to S is twenty six S minus eight.
So S minus twenty six, twenty six minus twenty four gives you two and twenty six, minus eight gives
you eighteen.
So these are the values over here, Bergeron's formula.
So on solving this you will get the area as twelve root thirty nine.
Now we know that the area also can be found as the product of the in radius and the semi perimeter that's
our into S and that is equal to R into twenty six, therefore twelve root thirty nine is equal to are
in the twenty six or eight is equal to twelve root thirty nine by twenty six or it simplifies as.
Six RWD thirty nine divided by 13, and that is your answer.