Let's do these questions.
Two are different angles of the program are in the ratio, four is to five, find their measures, post
the video, give it a try.
Let's do it together after that.
All right.
We're back.
It's given that the ratio of two at different angles is four to five to let those two angles before
X and five X, right.
Because if it's four and five X, if you take the ratio, which is nothing but dividing these two,
X will get canceled out and the ratio will be four to five.
Now, we know that in a program, the opposite sides are parallel, right?
Therefore, these two sides are parallel and this is a transversal.
Therefore, these two angles are consecutive interior angles.
Right.
Therefore, for X plus five, X is equal to 180 degree and hence you get X is equal to twenty degree.
And that gives you the angles as four in the twenty.
That's eight and five in the twenty.
That's hundred degrees.
All right.
Let's do the second question in a parallel.
Grampy.
Q Are is the bicyclers of Angle B and you meet at all find angle B OCU.
Alright, so we have A Barlowe Grumpy.
Q us over here.
Let the basic does of Angle P and Q meet at all and we need to find Angle poke you.
All right.
Past the video.
Give it a try and then let's do it together.
Alright.
We're back.
I hope you have given it right.
Let's do it together.
Let me mark the angles of triangle P.
Q as angle one to an angle three.
Now we know that angle B which is s p q right.
Angle B plus angle Q is equal to 180 degree because I just said angles are supplementary in that program.
All right.
And we have seen why that is in this case also.
Alright, so angle B plus angle Q is equal to 180 degrees, therefore angle one which is angle P by
to an angle to which angle.
Q By two.
If you add them you will get one eight by two.
Right.
That is ninety degrees y because angle one is angle B by two.
Right.
And angle two is angle Kubi two because these are angle bicyclers.
Right.
Therefore you know that in a triangle the sum of the angles is equal to 180 degrees.
Therefore angle one plus angle two plus angle three is 180 degrees.
And over here, you know angle one plus angle two is ninety degrees.
Therefore you get angle three is equal to ninety degrees.
All right.
Now let's do the third question in a bar logarithm peak.
You are as if angle B sixty degrees then what are the other three angles was the variable.
Give it a try and then let's do it together.
All right.
We are back.
I hope you have given it a try.
Let's do it together now.
It's given that one angle is sixty degrees.
Therefore the angle adjacent to it has to be one twenty degrees.
Right.
Because I just said angles add up to 180 degrees in Eppalock room.
So we have two angles.
Now we know that opposite angles in a Graham are equal to the angle, opposite to this angle should
also be sixty and the angle opposite to this angle should also be one twenty degrees.
Right.
Therefore the angles are sixty, sixty, one twenty and one twenty, which is option B..
Over here.