1 00:00:00,810 --> 00:00:02,250 Let's do these questions. 2 00:00:03,490 --> 00:00:10,390 Two are different angles of the program are in the ratio, four is to five, find their measures, post 3 00:00:10,390 --> 00:00:11,550 the video, give it a try. 4 00:00:11,860 --> 00:00:13,390 Let's do it together after that. 5 00:00:13,790 --> 00:00:14,200 All right. 6 00:00:14,200 --> 00:00:14,680 We're back. 7 00:00:14,950 --> 00:00:20,950 It's given that the ratio of two at different angles is four to five to let those two angles before 8 00:00:20,950 --> 00:00:22,300 X and five X, right. 9 00:00:22,540 --> 00:00:27,340 Because if it's four and five X, if you take the ratio, which is nothing but dividing these two, 10 00:00:27,580 --> 00:00:30,850 X will get canceled out and the ratio will be four to five. 11 00:00:31,180 --> 00:00:35,940 Now, we know that in a program, the opposite sides are parallel, right? 12 00:00:36,130 --> 00:00:39,940 Therefore, these two sides are parallel and this is a transversal. 13 00:00:40,180 --> 00:00:44,980 Therefore, these two angles are consecutive interior angles. 14 00:00:44,980 --> 00:00:45,340 Right. 15 00:00:45,520 --> 00:00:51,730 Therefore, for X plus five, X is equal to 180 degree and hence you get X is equal to twenty degree. 16 00:00:52,090 --> 00:00:55,240 And that gives you the angles as four in the twenty. 17 00:00:55,450 --> 00:00:57,700 That's eight and five in the twenty. 18 00:00:57,700 --> 00:00:58,750 That's hundred degrees. 19 00:00:59,050 --> 00:00:59,530 All right. 20 00:00:59,860 --> 00:01:02,280 Let's do the second question in a parallel. 21 00:01:02,290 --> 00:01:02,780 Grampy. 22 00:01:02,800 --> 00:01:09,400 Q Are is the bicyclers of Angle B and you meet at all find angle B OCU. 23 00:01:09,670 --> 00:01:12,070 Alright, so we have A Barlowe Grumpy. 24 00:01:12,070 --> 00:01:13,360 Q us over here. 25 00:01:13,660 --> 00:01:19,330 Let the basic does of Angle P and Q meet at all and we need to find Angle poke you. 26 00:01:19,630 --> 00:01:20,020 All right. 27 00:01:20,020 --> 00:01:20,800 Past the video. 28 00:01:20,800 --> 00:01:23,020 Give it a try and then let's do it together. 29 00:01:23,380 --> 00:01:23,800 Alright. 30 00:01:23,800 --> 00:01:24,280 We're back. 31 00:01:24,520 --> 00:01:25,810 I hope you have given it right. 32 00:01:25,990 --> 00:01:27,100 Let's do it together. 33 00:01:27,280 --> 00:01:29,500 Let me mark the angles of triangle P. 34 00:01:29,500 --> 00:01:32,410 Q as angle one to an angle three. 35 00:01:32,770 --> 00:01:37,270 Now we know that angle B which is s p q right. 36 00:01:37,390 --> 00:01:44,550 Angle B plus angle Q is equal to 180 degree because I just said angles are supplementary in that program. 37 00:01:44,800 --> 00:01:45,250 All right. 38 00:01:45,250 --> 00:01:48,310 And we have seen why that is in this case also. 39 00:01:48,590 --> 00:01:55,060 Alright, so angle B plus angle Q is equal to 180 degrees, therefore angle one which is angle P by 40 00:01:55,060 --> 00:01:57,220 to an angle to which angle. 41 00:01:57,220 --> 00:01:57,910 Q By two. 42 00:01:57,910 --> 00:02:00,490 If you add them you will get one eight by two. 43 00:02:00,670 --> 00:02:00,970 Right. 44 00:02:00,970 --> 00:02:06,220 That is ninety degrees y because angle one is angle B by two. 45 00:02:06,550 --> 00:02:06,880 Right. 46 00:02:06,880 --> 00:02:11,320 And angle two is angle Kubi two because these are angle bicyclers. 47 00:02:11,590 --> 00:02:11,900 Right. 48 00:02:12,160 --> 00:02:17,050 Therefore you know that in a triangle the sum of the angles is equal to 180 degrees. 49 00:02:17,200 --> 00:02:21,520 Therefore angle one plus angle two plus angle three is 180 degrees. 50 00:02:21,730 --> 00:02:25,030 And over here, you know angle one plus angle two is ninety degrees. 51 00:02:25,270 --> 00:02:29,100 Therefore you get angle three is equal to ninety degrees. 52 00:02:29,770 --> 00:02:30,210 All right. 53 00:02:30,460 --> 00:02:33,820 Now let's do the third question in a bar logarithm peak. 54 00:02:33,820 --> 00:02:39,910 You are as if angle B sixty degrees then what are the other three angles was the variable. 55 00:02:39,910 --> 00:02:42,250 Give it a try and then let's do it together. 56 00:02:42,850 --> 00:02:43,300 All right. 57 00:02:43,300 --> 00:02:43,810 We are back. 58 00:02:43,930 --> 00:02:45,370 I hope you have given it a try. 59 00:02:45,550 --> 00:02:47,350 Let's do it together now. 60 00:02:47,350 --> 00:02:49,900 It's given that one angle is sixty degrees. 61 00:02:50,080 --> 00:02:53,920 Therefore the angle adjacent to it has to be one twenty degrees. 62 00:02:53,920 --> 00:02:54,190 Right. 63 00:02:54,340 --> 00:02:58,470 Because I just said angles add up to 180 degrees in Eppalock room. 64 00:02:58,630 --> 00:02:59,770 So we have two angles. 65 00:02:59,950 --> 00:03:06,340 Now we know that opposite angles in a Graham are equal to the angle, opposite to this angle should 66 00:03:06,340 --> 00:03:11,210 also be sixty and the angle opposite to this angle should also be one twenty degrees. 67 00:03:11,210 --> 00:03:11,490 Right. 68 00:03:11,710 --> 00:03:17,230 Therefore the angles are sixty, sixty, one twenty and one twenty, which is option B.. 69 00:03:17,230 --> 00:03:17,890 Over here.