1
00:00:00,880 --> 00:00:08,020
Let's do this question in the given figure, A, B, C, D, and B, B, C, E, R, parallelograms

2
00:00:08,290 --> 00:00:17,410
with common base D.C. If B, C is perpendicular to be D, then B, C, you need to find this angle over

3
00:00:17,410 --> 00:00:17,760
here.

4
00:00:18,160 --> 00:00:18,550
All right.

5
00:00:18,550 --> 00:00:21,610
Pause the video, give it a try and then let's do it together.

6
00:00:22,030 --> 00:00:23,010
All right, we're back.

7
00:00:23,020 --> 00:00:24,000
Let's do it together.

8
00:00:24,190 --> 00:00:28,240
Over here we have angle BCT is equal to thirty degrees.

9
00:00:28,240 --> 00:00:28,590
Right.

10
00:00:28,750 --> 00:00:29,640
Why is that so.

11
00:00:29,800 --> 00:00:35,160
Because opposite sides of a bananagrams are equal and ABCDE is given as a program.

12
00:00:35,320 --> 00:00:39,850
Therefore if this angle is thirty degrees, this angle also has to be thirty degrees.

13
00:00:40,060 --> 00:00:40,480
All right.

14
00:00:40,660 --> 00:00:46,580
Now over here we have a triangle BDC One angle is ninety degrees, another angle is 30 degrees.

15
00:00:46,630 --> 00:00:50,770
Or what would be angle B C that would be 180 minus 90.

16
00:00:50,770 --> 00:00:51,700
Minus 30.

17
00:00:51,730 --> 00:00:52,050
Right.

18
00:00:52,420 --> 00:00:54,250
That's equal to sixty degrees.

19
00:00:54,580 --> 00:00:55,010
All right.

20
00:00:55,240 --> 00:00:56,830
So you have 60 degrees over here.

21
00:00:57,010 --> 00:01:02,140
Now, BDC is a bad anagram and opposite angles of a programmer are equal.

22
00:01:02,290 --> 00:01:07,840
Therefore, angle B C is equal to Angle BDC, which is equal to sixty degrees.

23
00:01:08,080 --> 00:01:11,290
And hence that's your answer, which is option eight.