1
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Let's do this question in figure ABCDE is a program, OK, so we have a program over here and a B is

2
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equal to eight centimetre and eight is equal to six centimeter.

3
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So we know the sounds of the program and the altitude is equal to for centimeter find the altitude corresponding

4
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to side 80.

5
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What would be the altitude corresponding to side 80?

6
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You need to identify the side.

7
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Well, what are the vertices opposite to decide either C or B right now, either from C or B, you need

8
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to drop A perpendicular to this site to find the corresponding altitude.

9
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Now, pause the video, give it a try, and then let's do it together.

10
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All right.

11
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We're back.

12
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I hope you've given it a try.

13
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Right now.

14
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We need to find the altitude corresponding to site 80.

15
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Let's mark the information given in.

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The question we know is equal to eight.

17
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Eight is equal to six and eight is equal to or.

18
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Now, what is the area of this program area is equal to basing the height.

19
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So if I take about as the base, that would be a B into 80.

20
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Right.

21
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So that's eight in four, which gives me 32 centimeters square.

22
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All right.

23
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Now, let me extend this side over here, OK?

24
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And let me draw a perpendicular form pointed to B, C.

25
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But over here, I get deep right now, we need to find the already corresponding to site 80, so that

26
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means it's the perpendicular distance between 80 and VXI, right.

27
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So, in fact, you can just see any point along this line and drop it perpendicular to this line.

28
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It would give you the same height.

29
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Even if I take this point right or this point, if I drop a perpendicular, the distance between two

30
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parallel lines is always the same.

31
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Right.

32
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So if I extend it and drop it perpendicular from here to here, or if I extend BCU and rather perpendicular

33
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from D to this side, it's one and the same for your understanding.

34
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Let me do it like this in this case.

35
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Right.

36
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So I have extended back and I have dropped the perpendicular from Vertex B to the extended line over

37
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here.

38
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So that's deep over here.

39
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Now we know that area is basically the height.

40
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So if I take it as the base, the height is deep over here to area is equal to 80 into height.

41
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Right.

42
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Height is deep when it is the base.

43
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Now, therefore, it goes into deep.

44
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Also has to be equal to thirty two.

45
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Now it's given that it is equal to six to six into deep is equal to 32 and hence deep is equal to 32.

46
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Divided by six.

47
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That gives you 16.

48
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Divided by three centimeter.

49
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And that's your answer.
