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Let's do this question if the area of a rectangle is 20 centimeter square and the length and breadth

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are integers, then find the maximum possible perimeter of the rectangle was the video.

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Give it a try and then let's do it together.

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All right.

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Let's do it together.

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Over here, we need to make the maximum possible perimeter, right, OK, so it's given that the area

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is equal to 25 centimeters square.

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Now, that means length into breadth is equal to any force.

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And this is constant right now.

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Perimeter is equal to two times length plus bread.

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And given that this is constant and we want to maximize length plus bread over here to maximize the

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sum when the product is constant, you need to keep in be as far apart as possible and then be entered

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into base twenty four.

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So how do you keep it as far apart as possible to do it as one in two twenty four to when you do it

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in this manner.

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The perimeter is equal to two times one plus twenty four.

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That gives you your answer as 50 centimeters.

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You don't need to construct all the possibilities and find the answer if you can remember this property.

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Now let's check whether our answer is correct.

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Now, what are all the possibilities?

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I could have twenty four in the one 12 to 18 to three or six into four.

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These are the four possibilities, right?

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In this case, my perimeter is two into twenty five, which is 50.

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And over here I have to window fourteen.

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That's twenty eight to Endou eleven.

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That's twenty to twenty ten.

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That's ten.

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So you can see that over here.

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I'm getting the maximum perimeter.

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So this is correct and the maximum possible perimeter is fifty centimetre.