Let's do this question if the area of a rectangle is 20 centimeter square and the length and breadth
are integers, then find the maximum possible perimeter of the rectangle was the video.
Give it a try and then let's do it together.
All right.
Let's do it together.
Over here, we need to make the maximum possible perimeter, right, OK, so it's given that the area
is equal to 25 centimeters square.
Now, that means length into breadth is equal to any force.
And this is constant right now.
Perimeter is equal to two times length plus bread.
And given that this is constant and we want to maximize length plus bread over here to maximize the
sum when the product is constant, you need to keep in be as far apart as possible and then be entered
into base twenty four.
So how do you keep it as far apart as possible to do it as one in two twenty four to when you do it
in this manner.
The perimeter is equal to two times one plus twenty four.
That gives you your answer as 50 centimeters.
You don't need to construct all the possibilities and find the answer if you can remember this property.
Now let's check whether our answer is correct.
Now, what are all the possibilities?
I could have twenty four in the one 12 to 18 to three or six into four.
These are the four possibilities, right?
In this case, my perimeter is two into twenty five, which is 50.
And over here I have to window fourteen.
That's twenty eight to Endou eleven.
That's twenty to twenty ten.
That's ten.
So you can see that over here.
I'm getting the maximum perimeter.
So this is correct and the maximum possible perimeter is fifty centimetre.