Let's do this question, the parallel sides of a trapezius are 40 centimetre and 20 centimeter if it's
nonpolluting, sides are both equal and each being 26 centimeter, find the area of the trapezius.
All right.
All the video, give it a try and then let's do it together.
All right.
Now let's do it together.
Let's drop the perpendicular from A and B. That's AP and B Q over here.
Now let's mark the information that is given to us.
We know a B is equal to 20 and this is 40, and these two non sides are equal to 26 centimeters.
So that's given.
Now therefore, P Q also will be 20.
Right.
And let this be X and then this also will be X because we are dealing with an isosceles trapezius because
these two sides are equal.
So this is also X, this is also X and this is 20.
Now you can see that 20 plus two X is equal to forty this side over here.
Therefore X is equal to ten centimeter.
All right, now, over here.
Let this be it.
OK, so over here, triangle e deep is the right angle triangle.
Right.
Therefore, 26 square is equal to eight squared plus X Square as per Pythagoras theorem.
Now hence I can find it square as 26 square minus X square and X is equal to ten.
We have found that over here.
It's square is 26 square minus hundred.
That's six, seven, six minus under and you'll get it as five seventy six.
Now remember five seventy six is twenty four square.
If you don't remember that you can just factor five seventy six so you will get it.
As to the two in the twelve in the twelve to the square root of five.
Seventy six is 212.
That's twenty four over here.
Now we have found the height and we know the two sides.
Therefore area is equal to X by two in the twenty plus forty.
That's twenty four by two into sixty and you will get the answer.
Seven centimetres square.