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Let's do this question, the parallel sides of a trapezius are 40 centimetre and 20 centimeter if it's

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nonpolluting, sides are both equal and each being 26 centimeter, find the area of the trapezius.

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All right.

4
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All the video, give it a try and then let's do it together.

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All right.

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Now let's do it together.

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Let's drop the perpendicular from A and B. That's AP and B Q over here.

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Now let's mark the information that is given to us.

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We know a B is equal to 20 and this is 40, and these two non sides are equal to 26 centimeters.

10
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So that's given.

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Now therefore, P Q also will be 20.

12
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Right.

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And let this be X and then this also will be X because we are dealing with an isosceles trapezius because

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these two sides are equal.

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So this is also X, this is also X and this is 20.

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Now you can see that 20 plus two X is equal to forty this side over here.

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Therefore X is equal to ten centimeter.

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All right, now, over here.

19
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Let this be it.

20
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OK, so over here, triangle e deep is the right angle triangle.

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Right.

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Therefore, 26 square is equal to eight squared plus X Square as per Pythagoras theorem.

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Now hence I can find it square as 26 square minus X square and X is equal to ten.

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We have found that over here.

25
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It's square is 26 square minus hundred.

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That's six, seven, six minus under and you'll get it as five seventy six.

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Now remember five seventy six is twenty four square.

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If you don't remember that you can just factor five seventy six so you will get it.

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As to the two in the twelve in the twelve to the square root of five.

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Seventy six is 212.

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That's twenty four over here.

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Now we have found the height and we know the two sides.

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Therefore area is equal to X by two in the twenty plus forty.

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That's twenty four by two into sixty and you will get the answer.

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Seven centimetres square.
