1
00:00:00,650 --> 00:00:08,780
Let's do this question, the perimeter of a trapezius 52 centimeter and e nonpareil side is equal to

2
00:00:08,780 --> 00:00:09,590
10 centimeters.

3
00:00:09,590 --> 00:00:15,340
So it's an isolationist tropism with its height as eight centimeter its area is.

4
00:00:15,350 --> 00:00:20,330
So you need to find the area of the video, give it a try, and then let's do it together.

5
00:00:20,810 --> 00:00:21,350
All right.

6
00:00:21,350 --> 00:00:22,260
Let's do it together.

7
00:00:22,520 --> 00:00:28,340
We know that the area of trapezius is equal to its by two in to some of parallel sites.

8
00:00:28,760 --> 00:00:31,300
Now, let's take a rough diagram over here.

9
00:00:32,030 --> 00:00:33,920
Say this is the isosceles trapezius.

10
00:00:34,100 --> 00:00:34,460
Right.

11
00:00:34,760 --> 00:00:42,090
And let this be let this be these are the two parallel sides and let this be X and let this be X.

12
00:00:42,470 --> 00:00:50,840
Now you can see that A plus B can also be written as a millimeter of the tropism, minus two times X.

13
00:00:50,840 --> 00:00:51,230
Right.

14
00:00:51,500 --> 00:00:56,570
So let's do that, because over here we are given the perimeter and we are given the nonpareil side.

15
00:00:56,820 --> 00:01:00,410
So I can write this as eight by two because it is eight.

16
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Right.

17
00:01:00,710 --> 00:01:07,150
So this is eight by two in the perimeter, minus two times the normal size right over here.

18
00:01:07,190 --> 00:01:07,760
Mm.

19
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Minus two X gives you A plus B, right.

20
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So that would be eight by two in the 52, minus two in the ten and that's four in the 32 which gives

21
00:01:18,320 --> 00:01:21,760
us one twenty eight centimetre square the area.

22
00:01:21,770 --> 00:01:25,580
And that is your answer, which is option C over here.
