Let's do this question in the figure BSD is a rhombus, then the value of white minus X is all right.
What's the big deal?
Give it a try and then let's do it together.
All right.
We're back.
Let's do it together.
Let me mark these two angles as angle one and angle to.
All right, now you can see that Y is equal to 90 degree, right, y y 90 degree because the diagonals
of a rhombus bisect each other right now because of the same reason.
Angle two also will be equal to 90 degrees.
And you can see that too.
And why form a linear pair as well.
So angle two also is equal to 90 degrees.
All right.
Now, in this triangle, let me call this all in triangle or maybe you can see that we have 40 degrees.
One angle we have angle to equal to 90 degrees.
Therefore, we can find angle one because 40 plus angle two plus angle one is equal to 180 degrees.
And hence angle one is equal to 50 degrees.
Now, a rhombus is a partial Graham, right.
Therefore, this is parallel to be a..
Is acting as the transversal.
Therefore Angle X is equal to angle one because both of them are alternate interior angles.
And we have found that angle one is equal to 50 degrees, therefore X is equal to 50 degrees.
Now, as per the question, we need to find Y minus X, Y minus X is 90, minus 50.
That's equal to 40 degrees, which is option.