1
00:00:00,620 --> 00:00:04,560
Let's do this question asks parallel to Eddie.

2
00:00:04,840 --> 00:00:12,050
All right, and it's given that a B is equal to B.S. So these two sides are equal and that's equal.

3
00:00:12,050 --> 00:00:13,340
Do it all right.

4
00:00:13,490 --> 00:00:15,830
And if is equal to F.P..

5
00:00:15,860 --> 00:00:17,330
So these two sides are equal.

6
00:00:17,330 --> 00:00:21,800
If it's the midpoint of each find the ratio of any of EDC.

7
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That's this triangle over here to the area of FGB.

8
00:00:26,060 --> 00:00:27,420
That's this triangle over here.

9
00:00:27,620 --> 00:00:28,120
All right.

10
00:00:28,340 --> 00:00:31,770
Pause the video, give it a try and then let's do it together.

11
00:00:32,390 --> 00:00:32,810
All right.

12
00:00:32,810 --> 00:00:33,260
We're back.

13
00:00:33,290 --> 00:00:34,280
Let's do it together.

14
00:00:34,430 --> 00:00:35,850
I hope you have given it a try.

15
00:00:36,170 --> 00:00:39,470
Now let's join point B to E and Andy.

16
00:00:40,460 --> 00:00:47,330
All right, now let's start marking all the information that's already been given to us.

17
00:00:47,630 --> 00:00:49,250
All right, let me do it again over here.

18
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We know that Eddie and ACOR parallel, ABC and Eddie are equal and if is equal to FEMA.

19
00:00:58,340 --> 00:01:00,380
But that's the information that we have.

20
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All right, now.

21
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We have joined Ebbe and Beatty right now.

22
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In this way, we have divided this ship into six equal areas.

23
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Right.

24
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We had discussed this before.

25
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In this way, we have divided this ship into six equal areas.

26
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Now we need to find the ratio of any of EDC.

27
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That's this part.

28
00:01:22,610 --> 00:01:25,730
So for EDC, you have to pick one two.

29
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You're taking two parts, right?

30
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That's this part.

31
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And this part two from EDC.

32
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Now to find the area of F, a, B, you're just taking one part right there for the answer to this question

33
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is to divide it by one.

34
00:01:40,970 --> 00:01:41,330
Right.

35
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This is two and this is one that's about it.

36
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That is the answer.

37
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Wasn't that fast.

38
00:01:46,610 --> 00:01:51,800
Now, over here you can see that ECB is a parallelogram, right?

39
00:01:52,580 --> 00:01:54,120
Let's try to understand it now.

40
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Now, in the exam, you should have moved on to the next question.

41
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Just marking.

42
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It has to buy one.

43
00:01:59,330 --> 00:01:59,780
All right.

44
00:01:59,960 --> 00:02:01,960
Now, DCB is a battleground.

45
00:02:02,360 --> 00:02:02,950
All right.

46
00:02:03,080 --> 00:02:09,500
So area of triangle E, D, C, that's this part is equal to area of EBC.

47
00:02:11,020 --> 00:02:11,320
Right.

48
00:02:12,270 --> 00:02:17,550
All right, so these two are equal now you can see that these two are congruent, right?

49
00:02:17,560 --> 00:02:18,880
We have proved that before.

50
00:02:19,070 --> 00:02:22,340
Therefore, these two areas are also equal.

51
00:02:22,480 --> 00:02:29,590
Now, if the area of DCB is taken as a then these two will be of area Ebeye to.

52
00:02:31,100 --> 00:02:37,580
All right, now you can see that area of E. The beat, that's this part over here.

53
00:02:38,520 --> 00:02:47,850
That is also equal to EBITA because this area and DBC is also equal right to area of EDB is also equal

54
00:02:47,850 --> 00:02:48,840
to EBITA.

55
00:02:49,260 --> 00:02:56,610
Now you can see that Eddy, be it this part over here also gives you Eppalock.

56
00:02:56,910 --> 00:02:57,260
Right.

57
00:02:57,400 --> 00:02:59,340
But this part also is a program.

58
00:02:59,610 --> 00:03:06,050
So area of E, B, that is this part over here is equal to area of DB.

59
00:03:06,180 --> 00:03:07,530
That is this part over here.

60
00:03:08,690 --> 00:03:09,910
Let me write that over here.

61
00:03:10,300 --> 00:03:19,940
These two areas are equal, and if we take the area of EDV as a then each of these is equal to by two.

62
00:03:20,510 --> 00:03:20,940
All right.

63
00:03:21,350 --> 00:03:24,530
Now, why have we taken the area of EDB?

64
00:03:24,530 --> 00:03:27,590
Is it as well as the area of Iraq?

65
00:03:27,680 --> 00:03:29,070
B, as A right.

66
00:03:29,240 --> 00:03:30,760
What is the area of a program?

67
00:03:30,770 --> 00:03:32,410
It's based in the height.

68
00:03:32,420 --> 00:03:32,740
Right.

69
00:03:32,930 --> 00:03:37,310
You will see that these two have the same base that's over here.

70
00:03:37,310 --> 00:03:38,480
It's Abian over here.

71
00:03:38,480 --> 00:03:39,110
It's busy.

72
00:03:39,230 --> 00:03:41,210
And we know that they are of equal length.

73
00:03:41,450 --> 00:03:43,910
And these are between two parallel lines.

74
00:03:44,060 --> 00:03:46,470
So the height of these two also will be the same.

75
00:03:46,700 --> 00:03:49,490
That's why both of them are of equal area.

76
00:03:49,560 --> 00:03:49,940
All right.

77
00:03:50,150 --> 00:03:50,910
Now what?

78
00:03:50,930 --> 00:03:57,140
Over here you can see that the area of F a B is equal to half of EBITA.

79
00:03:57,410 --> 00:04:00,290
Right, because these two triangles are congruent.

80
00:04:00,500 --> 00:04:05,150
Therefore, the area of F a B is equal to Ebeye for now.

81
00:04:05,150 --> 00:04:12,020
Having established these things, you can find that the required ratio is Ebeye two.

82
00:04:12,020 --> 00:04:13,310
That's LDC, right.

83
00:04:13,520 --> 00:04:22,280
EDC is equal to EBI two and F maybe that's it by four so ebi to buy by four and that gives you the answer

84
00:04:22,280 --> 00:04:24,770
as to by one or two is to one.

85
00:04:24,860 --> 00:04:31,580
And that's the same thing that we got within two or five seconds in the beginning itself, just using

86
00:04:31,760 --> 00:04:33,710
graphical division method.
