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Let's do this question, find this ratio that is 80 of ABCDE to the area of Triangle Deep Cube, that

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is this triangle over here to the area of Triangle dequeue.

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That's this triangle over here.

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Alright, pause the video, give it a try and then let's do it together and do try to use graphical

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division method to find this answer because it'll save you a lot of time.

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All right.

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We we're back.

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I hope you've given it a try.

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Let's do it together now.

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Over here, you can see that it is 20 and DC is 20 centimeter.

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And it's given that this angle is 90 degrees.

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So ABCDE is a square.

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Right.

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And we know that area of a square is side square.

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So area of ABCDE is 20 to 20.

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That's four hundred.

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All right.

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Now let's drop it perpendicular from B, so Apison that means B also is equal to 10 or P is the midpoint

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of Abe.

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All right.

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Now, let me drop it perpendicular from B to let me see at our.

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All right.

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Now you can see that B R has divided this square into two parts of equal area.

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Remember that similar to the first problem we discussed in the introduction to graphical division.

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All right.

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So we have a party and BCR and each of these will be of equal area.

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So you have two hundred over here and two hundred over here.

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All right.

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Now, let's see, Beardie.

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There is a nine party over here.

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This is a diagonal to A, B, R, B, right.

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So this two hundred is divided into two by P.E.T..

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Right.

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You have triangle apre and triangle pedia and each of these will be of hundreds and hundreds centimetres

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square each.

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Right.

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So let's write that over here.

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You have a pretty standard annual periodical to handle, all right.

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Now, over here, it's given that QCA right there for Cubie also will be 10.

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That is.

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Q is the midpoint of beseen now from Q Let's draw a perpendicular touching 80 at S right.

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So over here you can see that esq, you see them will have an area of two hundred in a similar manner

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that we saw over here.

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And Kudi is a diagonal to skew.

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Therefore the area of Triangle Deek you see will be half of two hundred that is handed over here.

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Right.

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All right, let's proceed.

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Now you can see that or b, b, q that's all we BQ this is forming one by fourth of the area of the

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square.

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Can you see that.

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Why is that.

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So let's take any one over here.

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For example, you take P r we have seen that BBC R is half of the area of the square and over here again

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you divide it into two.

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Right.

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So this part will be half of half.

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That is one by four of the area of the square will be P q OK, so the area of barbecue will be one by

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four in the form that that's equal to a hundred.

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All right.

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Now P Q is a diagonal to be Q Right.

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And hence P Q is dividing it into two equal areas.

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Therefore the area of P, Q, B is half of hundert.

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That is equal to 50.

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Right.

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So let's mark that over here.

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Now let's try to find the answer.

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What would be the area of deep.

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Q That would be four hundred minus under plus 50 plus hundred.

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Right.

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So you just need to subtract these three from four hundred to get the deep.

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Q All right, let's write that over here.

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The area ODP, you will be four hundred minus hundred, minus hundred minus fifty and therefore the

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required area or the required ratio over here will be one that is to 150 is two hundred or that is the

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area of the square.

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We have that over here.

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150 is the area of deep.

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Q When you do this you will get one fifty.

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Right.

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And the area of Triangle DC.

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Q That would be a hundred.

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Alright, so you can note over here that using graphical division method we were able to do this question

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very fast.
