Let's do this question in the figure given below Beke, you are as is a square off site, twenty eight
centimeter and two semicircles are drawn inside of it with BQ and others as the diameters find the shaded
region again.
You should be able to do this in five seconds.
This is the same as finding the area of the square.
Minus area of the circle, right, because you have just changed the orientation, if you put this back,
if you change the orientation, these two areas together will form one complete circle.
Right.
All right.
Let's try to do it again so that you solidify your understanding or here you have R and R, therefore
to R is equal to twenty eight or R is equal to 14.
Right to the radius over here is 14 centimeter.
Now let's try to find the shaded area.
That's the area of the square procurers minus two times the area of the semicircle.
And this is the same thing as the area of the circle.
Right.
All right.
So that's twenty eight square, which is the area of the square, Epicurus, minus two times half of
by our square where R is 14.
Right.
And this simplifies to seven hundred and eighty four minus twenty two by seven into 14 into 14.
That's seven eighty four minus six one six.
And you get your answers.
One sixty eight.
Centimeter square.