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Let's do this question in the figure given below Beke, you are as is a square off site, twenty eight

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centimeter and two semicircles are drawn inside of it with BQ and others as the diameters find the shaded

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region again.

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You should be able to do this in five seconds.

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This is the same as finding the area of the square.

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Minus area of the circle, right, because you have just changed the orientation, if you put this back,

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if you change the orientation, these two areas together will form one complete circle.

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Right.

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All right.

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Let's try to do it again so that you solidify your understanding or here you have R and R, therefore

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to R is equal to twenty eight or R is equal to 14.

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Right to the radius over here is 14 centimeter.

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Now let's try to find the shaded area.

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That's the area of the square procurers minus two times the area of the semicircle.

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And this is the same thing as the area of the circle.

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Right.

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All right.

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So that's twenty eight square, which is the area of the square, Epicurus, minus two times half of

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by our square where R is 14.

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Right.

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And this simplifies to seven hundred and eighty four minus twenty two by seven into 14 into 14.

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That's seven eighty four minus six one six.

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And you get your answers.

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One sixty eight.

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Centimeter square.