Let's do this question as circle of maximum possible size is cut from a square sheet of board, subsequently
a square of maximum possible size is cut from the resultant circle.
What will be the area of the final square now?
Options out there, three by four of the original square, half of the original square, one by four
of the original square, two by three of the original square balls.
That will give it a try and then let's do it together.
All right.
We're back.
Let's do it together.
We have a square.
Then we have a circle.
And inside the circle, we have a square right now at the side of the square.
B now, the diameter of this circle, therefore, also will be equal to a light.
We have already seen that.
But for you understanding, let me again explain it all right.
Now, because this diameter is equal to a we can find the area of the circle if required.
Now, we don't need that.
Let's proceed over here.
You have a square, a smaller square.
Let it be of site B and we can see that this part that's the diagonal of the smaller square will be
equal to the radius in the two of the circle.
That is the diameter of the circle.
So it is equal to the diameter of the circle and the diameter of the circle is equal to the diagonal
of the smaller square.
That means it is equal to the diameter diagonal of the inner square.
Right.
That's equal to room to be right as the Pythagoras's theorem.
Therefore I have be equal to Ebeye Rouper or B Square is equal to a square by two and therefore the
area would be half the area of the original square.
Now it should not take you this much time because this is already something that we have discussed so
directly.
You should have marked answer B as the answer.