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Let's do this question as circle of maximum possible size is cut from a square sheet of board, subsequently

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a square of maximum possible size is cut from the resultant circle.

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What will be the area of the final square now?

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Options out there, three by four of the original square, half of the original square, one by four

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of the original square, two by three of the original square balls.

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That will give it a try and then let's do it together.

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All right.

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We're back.

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Let's do it together.

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We have a square.

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Then we have a circle.

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And inside the circle, we have a square right now at the side of the square.

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B now, the diameter of this circle, therefore, also will be equal to a light.

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We have already seen that.

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But for you understanding, let me again explain it all right.

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Now, because this diameter is equal to a we can find the area of the circle if required.

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Now, we don't need that.

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Let's proceed over here.

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You have a square, a smaller square.

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Let it be of site B and we can see that this part that's the diagonal of the smaller square will be

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equal to the radius in the two of the circle.

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That is the diameter of the circle.

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So it is equal to the diameter of the circle and the diameter of the circle is equal to the diagonal

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of the smaller square.

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That means it is equal to the diameter diagonal of the inner square.

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Right.

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That's equal to room to be right as the Pythagoras's theorem.

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Therefore I have be equal to Ebeye Rouper or B Square is equal to a square by two and therefore the

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area would be half the area of the original square.

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Now it should not take you this much time because this is already something that we have discussed so

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directly.

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You should have marked answer B as the answer.