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High students in this video, let's continue learning about properties of Sakalys, all right, over

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here, I have a circle with Center all, and you can see that a B is an arc.

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And this arc is suspending an angle at point B, but that's angle APB.

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All right.

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Now, an interesting property of Sakalys is that the SUB-STANDARD angle is half the measure of the arc.

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Now, what is the measure of ARCHABBEY?

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That's the angle.

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It will be right.

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We have seen before that the measure of an arc is the angle that it's substance at the center of the

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circle.

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So the measure of Arc AB is angle will be.

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And as per this property angle, EPB is equal to half of angle.

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It will be.

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Now let's try to understand why this is so.

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Let me join P to all and extended two point or.

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Why do this construction over here that at this point over here?

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All right, now, what can you tell me about anger or be this anger over here?

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You can see that angle or B is equal to Angle or B, B plus angle or B, B, right.

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That's this angle.

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Plus this angle.

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Why is that so?

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Because Angle or B is an exterior angle.

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Or Triangle or Bebe.

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Right, and we have learned that in triangles, the exterior angle is equal to the sum of the interior,

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opposite angles to Orombi is an exterior angle and angle.

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OPV and Angle or BP are the interior opposite angles.

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Right.

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But that's why this is true.

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Now, over here you can see that OPIS is equal to Olby.

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These two are equal because these two are really irate or Pissarides and Albie's radius.

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Therefore OPIS equal to or B and hence Triangle or B is an isosceles triangle.

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Therefore, we know that these two angles, that is the angles opposite equal sides are equal in an

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isosceles triangle.

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So these two will be equal, right.

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So let me call it as two times angle or B.

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So we have seen that R or B is equal to two times or B, B, similarly, you can see that R or A.

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Let me write that over here, or it will be equal to two times and will all be.

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With the same logic now, if you add up these two together, if you add up these two together, that

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should be equal to adding up these two together.

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So if you add up R or B Ainaro, you will get A, B or C, that's this angle over here.

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Over here.

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By adding it up, you get angle B or it's the same as angle AOB.

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And when you add up these two together, right, you get two times angle A, B, B, right.

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This plus this gives EPB and over here you have two, over here you have a two that's two times EPB.

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So therefore you can see that angle.

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It will be divided by two gives angle EPB.

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That's what we got over here.

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So let's quickly revise the property in a circle.

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If you have an arc and the arc is attending an angle over here, therefore this angle that is angle

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APB will be half the measure of the arc.

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That is half of angle.

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It will be all right.

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Now, let me make some space over here.

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Now, over here, we have taken our job as the main Iraq right now, what would have been the case if

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Archabbey was the major Iraq?

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Let me draw that over here.

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So I have a circle, right?

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I have Alawa here and I have B over here.

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Now we are taking the meds, Iraq.

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So that's this sakova here.

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Right.

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Let this be the center to the measure of the major arc, is this angle right?

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OK, let me call this as to top then, if you take an angle over here, let me make this point a point

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B that I join it with, and B, to this angle over here will be half of this.

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That's theater.

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So you need to take it in the correct order.

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If you're taking the arc as the major arc, then you need to take an angle on this side of the major

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arc.

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Right.

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If you're taking as a minor arc, then you need to take an angle on this side.

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That's the other side of the arc.

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Right.

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In that case, if this is the order, then this will be to data.

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In this case, if this measure is detailed, then this angle over here will be tighter.

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Now, let me tell you one more interesting thing.

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If you take this point, Peter's over here and join and Peter's right.

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Let me make it a straight line.

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All right, now over here, you can see that A, B, B and B, B Rush are all four points on a circle,

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right?

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Later, we will learn that A, B, B, B dash is actually a cyclic quadrilateral.

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We will learn about that and in a cyclical little the some of the opposite angles is equal to 180 degrees.

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So this angle teeter over here and this angle will be adding up to 180 degrees.

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So if this is the order, then this angle over here will be 180 minus detail.

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And what would be the measure over here?

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We have learned that this will if this is done, this has to be to deter.

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So this measure over here has to be two times 180 minus detA.

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Right.

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That's 360 minus two data.

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And that is also valid with what we have learned.

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Right.

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If this is Dieter, we have learned that this is true, Dieter, and we know that this is one complete

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revolution around a point that's equal to 360 degree.

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So if this is true, Dieter, then this measure over here will be 360 minus two.

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Dieter And that is what we have got over here.

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All right.

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Let me quickly summarize the points that we have learned so far.

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We have seen that you take an hour and you make a point P over here and you make an angle APB.

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Then if this is true, this will be equal to Dieter.

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That's our first learning.

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The second learning is that we should take the right arc.

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So in this case, we are taking Archabbey as the minor arc and hence we had to take a point over here

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so that this one is the ratio is maintained right now.

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If you are taking the major arc, then you need to take a point over here.

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And if you join it together, it will still be a one to two ratio.

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That is, if this angle is titta, this measure of the major arc will be to titta.

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That's our second learning.

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Right.

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And we have also seen that if I join A, B, B and B, that it's forming a cyclic quadrilateral.

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We will learn more about cyclic Waldron's later.

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But in this case, if this is Dieter, then this will be 180 minus Dieter because the angles which are

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opposite to each other in a cyclic quadrilateral are supplementary.

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And we have seen that this holds over here you get three 60 minus two Titta.

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And that is also true in the other way.

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If we take this as two to then because this forms one complete revolution.

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Therefore also this angle over here has to be 360 minus two to.
