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Students so far, we have learned a lot of interesting properties of Sakalys, let's learn one more

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interesting property over here.

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Over here I have a circle with center or let me draw a diameter for this circle and let the diameter

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be.

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And let me take a point B over here.

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Now, you can see that if I join A and B and B and B and remember, EBR is the diameter in this case

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angle, EPB will be equal to 90 degrees.

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So this is also very important property.

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Can you tell me why this is so?

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Let's discuss that together over here.

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We had seen that angle.

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EPB is equal to half of angle.

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It will be right for the angle, something that is equal to half of the measure of the arc.

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Right.

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All right.

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This is just an application of this property that we have discussed before.

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Why in this case, what is the measure of Archabbey, the measure of our AB?

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Over here is equal to 180 degree rate because it's a straight line is the diameter, this angle over

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here is equal to 180 degree.

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Therefore, we have seen as per this property, the angles attended by EBE should be half of 180 degree

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to this angle EPB Hans's 180 divided by two.

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That's why we get this angle as 90 degrees.

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All right, let's quickly revise these properties that we have learned.

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We have seen that the angle substandard by an arc is equal to half the measure of the arc.

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So that's this property over here and we have seen that the angles suspended by the same arc will be

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equal.

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That is over here.

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EPB will be equal to Engvall, AQAP.

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That's the second property that we learned over here.

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We have discussed that if you have two court A, B and B are over here.

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If Angle or B is equal to and will be are then A, B will be equal rupia.

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And the reverse is also true.

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If you have two equal courts, then their measures will be equal.