Students so far, we have learned a lot of interesting properties of Sakalys, let's learn one more
interesting property over here.
Over here I have a circle with center or let me draw a diameter for this circle and let the diameter
be.
And let me take a point B over here.
Now, you can see that if I join A and B and B and B and remember, EBR is the diameter in this case
angle, EPB will be equal to 90 degrees.
So this is also very important property.
Can you tell me why this is so?
Let's discuss that together over here.
We had seen that angle.
EPB is equal to half of angle.
It will be right for the angle, something that is equal to half of the measure of the arc.
Right.
All right.
This is just an application of this property that we have discussed before.
Why in this case, what is the measure of Archabbey, the measure of our AB?
Over here is equal to 180 degree rate because it's a straight line is the diameter, this angle over
here is equal to 180 degree.
Therefore, we have seen as per this property, the angles attended by EBE should be half of 180 degree
to this angle EPB Hans's 180 divided by two.
That's why we get this angle as 90 degrees.
All right, let's quickly revise these properties that we have learned.
We have seen that the angle substandard by an arc is equal to half the measure of the arc.
So that's this property over here and we have seen that the angles suspended by the same arc will be
equal.
That is over here.
EPB will be equal to Engvall, AQAP.
That's the second property that we learned over here.
We have discussed that if you have two court A, B and B are over here.
If Angle or B is equal to and will be are then A, B will be equal rupia.
And the reverse is also true.
If you have two equal courts, then their measures will be equal.