Let's do this question, what is the center of the circle?
Find angle deep, B, that's B, B, B, this is the angle that we need to find given angle sees equal
to 40 degree and angle déby be a B, that's include 30 degrees already.
Pause the video, give it a try and then let's do it together.
All right, let's do it together.
Let's mark the information that's given.
We know that this angle is 40 degrees and it's given that angle, Déby is equal to 30 degrees.
All right.
Now you can see that angle.
B, it will be equal to angle, Betty.
Right, because these are SUB-STANDARD by the same arc.
Right.
So Angle B, Ed, this angle over here will be equal to and will be.
And we know this is 30 degrees.
So this angle also will be equal to 30 degrees.
All right.
Now we know that angle, EBC, B, C, right.
This angle over here will be 180, minus 30, minus 40.
Right.
Because EBC is forming a triangle triangle EBC is 180, minus 30, plus 40.
That's equal to one one zero degrees.
So let's get over here.
OK, now you can see that angle, ABC, that's this angle over here from the linear pair with this angle
over here, that's angle NBC right to this.
Plus this should be 180 degrees.
So I can see that angle, EBD 180 minus angle EBC.
That's 180 minus one hundred and ten degrees, which gives you 70 degrees.
Right at this angle over here will be 70 degrees.
Now what about angle A, B, E and angle A, B?
You will see that both of these angles that this angle and this angle over here are substandard by the
same arc.
Right, Tamani?
Therefore, these two are equal.
That's about equal to angle 80.
And hence this angle over here is also equal to 70 degrees.
All right.
Now, let's continue.
We know that angle, EDV angle E, the B, right.
That will be 90 degrees because EBR is the diameter.
And we know that the angle SUB-STANDARD by the diameter is equal to 90 degrees.
With this angle over here is the right angle.
And so you can see that angle.
CDB is also 90 degrees, right.
Because this angle that KDB and EDB form a linear pair.
So this and this should add up to 180 degrees because this is ninety degrees.
This angle over here also will be 90 degrees.
All right, let's mark that, OK?
Now you can see that angle, PTB, that's B B B is equal to 90 minus 70.
Right.
This whole angle is 90 degrees and this much is 70 or PDV.
That's this angle over here will be 90 minus 70.
That is equal to 20 degrees.
All right.
Now let's observe quadrilateral B, B, C, B, we know that the sum of the angles of a quarter has
to be 360 degrees.
Right?
So if you add this angle, plus beauty C plus BBC plus B KB, you should get 360 degrees.
So Angle DPB, which is the angle that we need to find out is equal to 360 minus one hundred and ten.
Minus 40, minus 90.
Plus 20.
Right.
So deep B this is the angle.
Why is this 90 plus 20.
Because we know that BDC is 90 and PTB we have found it is 20.
Therefore angle BDC right angle PDC is equal to 90 plus 20.
Now when you solve this, you will get the answer answers 100 degrees and that is your solution.