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Let's do this question, BQ is a diameter of the circle, or as is parallel to BQ, B are is equal to

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askew is equal to six centimeter.

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All right, find out.

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Just given that the radius of the circle is five centimeter was the video.

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Give it a try and then let's do it together.

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All right.

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We're back.

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Let's do it together.

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Now, over here.

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BQ is a diameter, right?

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And we know that the radius is five centimeter.

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Therefore, P Q is equal to two in the five.

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That gives you 10 centimeter.

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All right.

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Now it's given PR is equal to askew is equal to six centimeter.

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Let's mark that over here.

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So Paris six and Q is six.

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All right.

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Now let's join B and S all right.

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And you can see that angle P.

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Q is equal to 90 degrees, right?

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Why is that so?

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Because P Q is the diameter and we know that angle sub-standard by the diameter is the right angle to

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angle P Q is equal to 90 degrees.

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All right.

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Now in right angle triangle P Askew over here we have Pexton and ask us six.

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So using Pythagoras Theorem we can find a square root of ten squared minus six square that gives you

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sixty four square root of sixty four which is equal to eight already.

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So we got both.

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Now let the height through vertex is of triangle P, Q, B over here and let it be attached to the area

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of triangle pieces.

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Q can be found this half in two pieces into a skew.

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Right, because this angle is ninety degrees.

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We know area is half in the base in the height.

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But if I take a skew as the base as will be the height because this angle is ninety degrees to area

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of triangle Q is equal to half in the piece in the Q and if I take P Q as the base then this over here

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that is X is the height.

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So this same area will be equal to half in the etching.

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The P q now over here I have is equal to eight and askew is equal to six.

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Right.

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And P Q is equal to ten.

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So let me substitute that over here.

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So I get eight in the six is equal to each in 210 or solving it.

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I get it is equal to four point eight.

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All right.

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Now let's proceed.

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Let me drop a perpendicular from our also so that this one over here.

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Now, let me take this point, this point and let this distance AQ be equal to X.

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Now, consider the right angle triangle s AQ because this is a 90 degree angle.

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Right, because we dropped the perpendicular now in right angle triangle essay.

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Q You can see that skew is the hypotenuse and one side is edge and the other side is X.

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So six square is equal to eight squared plus X square.

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Now using this you can find that X squared is equal to six squared, minus four point eight squared

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because we found that it is equal to four point eight.

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Now remember is squared minus B square is equal to A, minus B into A plus B, right.

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So you must have known that in your algebra.

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So square is a square minus because it minus being A plus B, so I use that to solve this faster.

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So this becomes six minus four point eight in the six plus four point eight.

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That is one point two in two, ten point eight.

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All right.

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Let me make some space over here now on solving this.

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You can find that X is equal to square root of twelve point nine six, and that is equal to approximately

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three point six.

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In a previous video in the section on numbers, we had seen how to find the approximate square root.

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Right.

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If you don't remember that, please go and refer that variable.

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So that will help you to find this as three point six.

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Let me quickly summarize it over here, then you're screwed over here is square root of nine.

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That gives you three, right?

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So this is approximately square root of thirteen twelve point nine six.

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And that is approximately nine plus four right now.

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Square root of nine is three and you are left with four.

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So this becomes three plus four, divided by two in three D three.

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Right.

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So that's three plus four by six.

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And that gives you three point six.

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Right.

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Because four by six point six.

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Six six extra.

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So I take you this point six.

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All right.

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Let me make some space over here.

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So we have found that the value of X is approximately three point six.

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All right, now we need to find our S from this diagram, you can see that Otter's is equal to that

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is equal minus X, minus X.

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This also will be x rayed because these two triangles are congruent because this is also six is also

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six.

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Right.

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So this is also X.

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This is also X, so 10 minus two.

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That is ten minus two in the three point six.

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We'll give you the value of our X.

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And that is equal to two point eight centimeter, and that is the solution to this question.
