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Let's do this question, the two circles in the finger have really a four centimeter and three centimeter

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or Anmar centers Angle or M is 90 degree, that's all m find a B, it is the common second.

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All right.

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Pause the video, give it a try and then let's do it together.

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All right, we're back.

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Let's do it together.

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Let me join or an M or an E or an M and the same thing over here will be and B m.

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All right.

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Now what we hear, it's given that there are four and three centimeter, so let or maybe four centimeter

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and M B three centimeter.

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Now you can see that or A M B or M B this shape over here is a quite right.

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Because or A and or B border, four centimeter and M and M B border three centimeter, because these

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two are really in these two already because there are two sets of adjacent sites that are equal.

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That's why IMB is a kite.

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And remember, in a kite, the diagonals intersect at 90 degrees.

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So we can say that this angle over here is also 90 degrees.

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All right.

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Now it is given that it is a 90 degree angle.

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So this angle also is 90 degrees.

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All right.

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Now, let the point of intersection of or M and A, B, B, B, so I take this point A point B now we

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have seen that angle or M is 90 degrees.

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Therefore we can say that or M is equal to the square root of four squared plus three square.

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Right.

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Because all M is the right angle triangle.

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So as per Pythagoras theorem or M a square root of four squared plus three square that gives you five

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or M is equal to five.

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All right.

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Now let's take triangles or erm now what would be the area of this triangle that would be half in the

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base in the height right now if I take or erm as the base that would be half in two or M into epeat.

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All right.

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Let me right that over here.

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That's half in two or M in two AP Now I could take em also as the base.

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If I take em as the base, the area would be half in to em and do it right, because over here you have

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a right angle.

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Therefore, or itself is the altitude troop.

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Therefore, the area is also equal to half way into em.

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Now let me substitute values.

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I get um, as five over here, right there for AP in the five is equal to three, two, four.

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We know these two Seitzer three and four to Eppy into five is three and four on solving you get a B..

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That's this much over here as two point four now B also will be equal to AP, right.

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Therefore AB is equal to two times two point four.

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That is equal to four point eight centimeter, which is your answer.