Let's do this question, the two circles in the finger have really a four centimeter and three centimeter
or Anmar centers Angle or M is 90 degree, that's all m find a B, it is the common second.
All right.
Pause the video, give it a try and then let's do it together.
All right, we're back.
Let's do it together.
Let me join or an M or an E or an M and the same thing over here will be and B m.
All right.
Now what we hear, it's given that there are four and three centimeter, so let or maybe four centimeter
and M B three centimeter.
Now you can see that or A M B or M B this shape over here is a quite right.
Because or A and or B border, four centimeter and M and M B border three centimeter, because these
two are really in these two already because there are two sets of adjacent sites that are equal.
That's why IMB is a kite.
And remember, in a kite, the diagonals intersect at 90 degrees.
So we can say that this angle over here is also 90 degrees.
All right.
Now it is given that it is a 90 degree angle.
So this angle also is 90 degrees.
All right.
Now, let the point of intersection of or M and A, B, B, B, so I take this point A point B now we
have seen that angle or M is 90 degrees.
Therefore we can say that or M is equal to the square root of four squared plus three square.
Right.
Because all M is the right angle triangle.
So as per Pythagoras theorem or M a square root of four squared plus three square that gives you five
or M is equal to five.
All right.
Now let's take triangles or erm now what would be the area of this triangle that would be half in the
base in the height right now if I take or erm as the base that would be half in two or M into epeat.
All right.
Let me right that over here.
That's half in two or M in two AP Now I could take em also as the base.
If I take em as the base, the area would be half in to em and do it right, because over here you have
a right angle.
Therefore, or itself is the altitude troop.
Therefore, the area is also equal to half way into em.
Now let me substitute values.
I get um, as five over here, right there for AP in the five is equal to three, two, four.
We know these two Seitzer three and four to Eppy into five is three and four on solving you get a B..
That's this much over here as two point four now B also will be equal to AP, right.
Therefore AB is equal to two times two point four.
That is equal to four point eight centimeter, which is your answer.