Let's do this question in the figger B.C. is equal to be able to see every angle, B.C. is equal to
40 degrees.
Find Angle Beida.
All right, let's model the given information.
We have BK's, 40 degrees.
We know that because equal to B and C, D battling to be all right.
Now pause the video, give it a try and then let's do it together.
All right.
We are back.
Let's do it together over here.
It's given that BK's equal to a B, right.
Therefore, Angle BCA will be equal to angle B C, that's equal to 40 degree Y because C, B is forming
an isosceles triangle.
And we know that angles opposite equal sites in an isosceles triangle are equal already.
So we have found that angle.
BSI is equal to 40 degrees.
Now it is given that AB is parallel to C, right?
Let me write that over here about parallel to city, therefore angle BSE will be equal to ÀNGEL, right,
because these are alternate interior angles, but this angle over here will be equal to this angle over
here, right.
Abey's parallel to Kitty and he is acting as the transposon.
Now we found that this angle is 40 degrees.
Therefore Angle ACD also is equal to 40 degrees.
All right.
So this is also 40 degrees.
Now you can see that BCT is a cyclic quadrilateral, right?
Why is that so?
B, C, D, and the all the vertices are on the circle, so BCD is a cyclic quadrilateral and we know
that in a cyclic quadrilateral, opposite angles are supplementary, right?
Obesity plus B is equal to 180 degree.
Now or here, BCT is 40 plus 40, right, but that's 80 degrees, therefore you can find that angle
beauty is 180 minus 80.
That gives you the answer is 100 degree.
And that is your solution.