Let's do this question, find the area of the quadrilateral whose vertices are zero zero seven nine,
10, eight and 12, comma six.
All right, was the video.
Give it a try and then let's do it together.
Now, you can either take it as two triangles and then solve it, or you can also to solve it using
this formula that is you write the vertices in this manner, you put half over here, then you have
x1 y one extra Y two x three y three X for Y four and then you have again X and Y one.
And then it's the same method.
You multiply one by one by two x2 and Y three x three and four X and Y one.
Similarly you do this operation also that is x2 and Y one x3 and Y to x4 and Y three and X one and rifle.
Right.
And then you take the difference.
Let's apply it over here.
You have zero zero seven, nine, ten, eight and 12 six and then you cross multiply over here zero
into nine plus seven into eight plus ten in the six plus twelve in the zero.
That gives you one hundred and sixteen.
Right.
OK.
And seven to zero then in the nine plus twelve in the eight plus zero in the six that gives you one
eighty six.
Right.
Therefore the A's have in two one one six minus one eighty six and you always take the positive value
but that's seventy divided by two and that gives you the answers.
Thirty five units square.