1
00:00:00,520 --> 00:00:06,400
Let's do this question, find the distance between the centroid and sock'em center of a triangle with

2
00:00:06,400 --> 00:00:10,780
coordinates 12 comma zero zero, comma 12 and 12 12.

3
00:00:11,050 --> 00:00:11,480
All right.

4
00:00:12,140 --> 00:00:14,920
Also, we will give it a try and then let's do it together.

5
00:00:15,130 --> 00:00:17,450
Remember to start by plotting the points.

6
00:00:18,040 --> 00:00:18,490
All right.

7
00:00:18,490 --> 00:00:19,050
We are back.

8
00:00:19,090 --> 00:00:20,530
I hope you have given it a try.

9
00:00:20,620 --> 00:00:21,600
Let's do it together.

10
00:00:21,880 --> 00:00:23,540
So I have my access over here.

11
00:00:23,740 --> 00:00:25,760
Now, let me plot the three points.

12
00:00:25,780 --> 00:00:26,980
So this is 012.

13
00:00:27,190 --> 00:00:29,910
Is this 12, comma 12 and this is 12 comma zero.

14
00:00:30,400 --> 00:00:36,190
Let me join the points together and you can see that you are getting it right angled triangle right

15
00:00:36,400 --> 00:00:36,840
now.

16
00:00:37,000 --> 00:00:40,900
Therefore, the circle center is that midpoint of the hypotenuse.

17
00:00:40,900 --> 00:00:41,260
Right.

18
00:00:41,440 --> 00:00:46,000
Because we have seen that in the case of the right angle triangle, the circle center is the midpoint

19
00:00:46,000 --> 00:00:46,870
of the hypotenuse.

20
00:00:47,050 --> 00:00:49,290
And over here, this side is the hypotenuse.

21
00:00:49,300 --> 00:00:55,900
Therefore we get the circumstances zero plus twelve by two comma, twelve plus zero by two, right where

22
00:00:55,920 --> 00:00:56,520
you have zero.

23
00:00:56,530 --> 00:00:57,350
And this is 12.

24
00:00:57,580 --> 00:00:59,470
That's why zero plus twelve by two.

25
00:00:59,650 --> 00:01:05,800
Similarly of twelve over here and zero over here to 12 plus zero by two to the sock'em center is six

26
00:01:05,800 --> 00:01:06,670
comma six.

27
00:01:06,970 --> 00:01:07,370
All right.

28
00:01:07,630 --> 00:01:09,880
Now we know how to find the centroid, right.

29
00:01:10,060 --> 00:01:13,270
We just need to add all the coordinates and divide by three.

30
00:01:13,450 --> 00:01:17,410
And similarly, we need to add all the Y coordinates and divide by three.

31
00:01:17,680 --> 00:01:24,610
To the center of this triangle is zero plus 12 plus 12 by three, comma 12 plus 12, plus zero by three

32
00:01:25,180 --> 00:01:26,520
zero 12 and 12.

33
00:01:26,560 --> 00:01:27,010
That's over.

34
00:01:27,010 --> 00:01:29,680
We're here in 2012 and zero that's over here.

35
00:01:29,890 --> 00:01:34,530
Now this gives the centroid as twenty four by three comma.

36
00:01:34,540 --> 00:01:35,620
Twenty four by three.

37
00:01:35,830 --> 00:01:37,940
That's equal to eight comma eight.

38
00:01:38,260 --> 00:01:44,050
Now we have found the centroid and the sock'em center and we are asked to find the distance between

39
00:01:44,050 --> 00:01:44,990
these two points.

40
00:01:45,250 --> 00:01:50,710
Now we know how to find the distance between two points that would be square root of eight minus six,

41
00:01:50,710 --> 00:01:56,800
the whole square plus eight, minus six, the whole square that's root of two squared plus two square,

42
00:01:56,800 --> 00:01:58,660
which is equal to to rule two.

43
00:01:58,810 --> 00:02:00,340
And that is your answer.