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High students so far, we have learned the general way in which we can express the equation of a straight

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line.

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Right now, let's see the next way in which we write the equation of a straight line that is X by three

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plus Y by four is equal to one.

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But how do you get from here to here?

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That's right.

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This equation over here.

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That's four X plus three Y is equal to twelve.

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Now, if you divide this throughout by 12.

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Right.

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You'll get to this equation over here.

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Let me show you how or here this becomes or X by 12.

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And I can write this as X divided by twelve.

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By four.

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Right.

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Plus this is three Y by 12.

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That can be written as Y divided by well by three and twelve by twelve is equal to one.

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So this twelve by four is your three over here and twelve by three is your four over here.

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Now the generic way of this form of writing the equation of a straight line is X divided by a plus Y

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divided by B is equal to one.

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All right, let me make some space over here.

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Now, there is some interesting things to note about this equation.

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This tree over here that you have is the X intercept, and this four is the Y intercept.

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What do I mean with that?

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Now, when X is equal to zero, right.

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Y is equal to four for this equation.

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That is what we call the Y intercept.

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That is X is equal to zero.

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You get Y is equal to four.

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Similarly, when Y is equal to zero, you get X is equal to three.

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And that is what we call the X intercept.

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Now let me mark these two points on our X Y plane over here.

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So that is three zero and this is zero for now.

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Let me join them together.

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Let's quickly discuss why this formula is true right now.

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Let's take any point.

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Be on this line.

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This is point B, X, Y.

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All right.

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Now, let me join B to the origin over here, OK?

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Now, let me mark these points.

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SPQR s OK, this is Q This is, this is this is ah.

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Now let's drop a perpendicular promise to y axis and the x axis.

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So that's about particular.

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And this is a perpendicular.

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All right.

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Now let this length over here be it.

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Right.

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And this is B right.

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Because over here we have E has the X intercept.

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That's E over here and over here we have B as the Y intercept.

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That is B over here already now and a nice triangle P Q are.

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So we have this triangle over here.

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Right.

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This is triangle P.

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Q are.

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You will see that the area of Triangle Peak you are is equal to offer in to be because the axes intersect

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at right angles.

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All right, now, another way of finding the area of this triangle peculiar would be finding the area

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of Triangle B askew, right.

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Triangle B, rescue plus area of triangle on.

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Right, so this this triangle over here is askew, this one over here.

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Yes, you are.

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All right.

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Now, what would be the area of Triangle B askew?

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That would be half being to this distance over here?

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Right.

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And what is this distance?

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This distance will be equal to X, right?

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Because this point over here is B, X, Y, but this distance is X right now.

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Therefore, this area will be half B into X.

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Similarly, this area will be half in the Y because this distance.

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Right.

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Is equal to it.

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Let me right that over here for you.

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This distance, right, is equal to X and this distance is equal to Y because we have taken B, X,

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Y.

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Now the area of Triangle BQE will be off being the X and the area of Triangle Square will be half in

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do Y, so that's equal to half B X plus half E white.

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All right.

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But make some space over here.

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Now, these two are equal, right, to let me cut out the half and I get a B is equal to B, X plus

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a Y now divided throughout with a B and you get X divided by eight is plus Y, baby is equal to one.

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And that is this equation which we discussed over here.
