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This is a debugging exercise.

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So this is code that you wrote ages ago where

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you created a program that tests whether

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if an input is an odd or an even number.

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Now, however I've put some bugs in there.

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So I've been sneaky, and I have messed

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up the code a little bit and this happens a lot to us

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programmers, sometimes we do it unintentionally.

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Sometimes somebody else messes with our code or sometimes

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we've just written something that's completely nonsensical

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and it doesn't do what we want it to do.

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This is a really important skill.

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This along with being good at Googling is probably one

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of the most important skills for a professional developer.

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Don't feel bad just

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because you know the code is wrong and you have to fix it.

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This is something that I expect all developers

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to get good at.

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Take a look at the code.

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You know what it has to do.

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It has to take any given input

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and tell you if it's even number or an odd number.

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Identify and fix mistakes in it

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and then feel free to hit Submit to see

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if your code passes all the checks.

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I strongly encourage you to not look

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at your previous solution for odd or even

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and to figure it out from first principles.

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Have a go now.

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The solution is pretty quick and simple

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but finding it is not quick and simple.

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Hopefully, you managed to figure out

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that the bug here is where we've got

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if number % 2 == 0,

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a single equal (=) in Python is an assignment,

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it's saying let's put the right side

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of the equal sign into the container that's on the left,

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whereas, two equal signs (==) is checking for equality.

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So is the left hand side equal

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in value to the right hand side?

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And that's what we need to do when we want to check

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if a number is odd or even.